A wire of 24 resistance is bent to form a square loop. A 10 V battery negligible internal resistance is connected across the diagonals of the square loop. The potential drop across one of its sides is:

Step-by-step solution

The total resistance of the wire is R = 24 . Since the wire is bent into a square loop, each side of the square has a resistance of r = 24 4 = 6 . When a battery is connected across the diagonals of the square, the loop is divided into two parallel branches. Each branch consists of two sides of the square connected in series. Thus, the resistance of each branch is R_ branch = 6 + 6 = 12 . The two branches are connected in parallel across the 10 V battery. Therefore, the potential difference across each branch is 10