The power dissipated across the 16 resistor in the circuit is 2 watts. The power dissipated in watt units across the 4 resistor is:

Step-by-step solution

The circuit consists of two parallel branches. The top branch contains a 16 resistor. The bottom branch contains a 6 resistor and a 4 resistor in series. Let V be the potential difference across the parallel branches. The power dissipated in the 16 resistor is given by P₁₆ = V^2 R₁₆ = 2 W. Substituting R₁₆ = 16 , we get V^2 16 = 2 , which implies V^2 = 32 V ^2 . The bottom branch has a total resistance R_ bottom = 6 + 4 = 10 . The current flowing through the bottom branch is I_ bottom = V R_ bottom = V 10 . The pow