The net resistance between the points A and B in the circuit given below is:

Step-by-step solution

A and E are the same node. The circuit forms a Wheatstone bridge with D and C as middle junctions. Arms: R_ ED = 4R , R_ EC = 2R , R_ DB = 4R , R_ CB = 2R , cross resistor = 5R Balance check: R_ ED R_ EC = 4R 2R = 2 and R_ DB R_ CB = 4R 2R = 2 Bridge is balanced no current through 5R , so it is removed. Upper branch (E-D-B): 4R + 4R = 8R Lower branch (E-C-B): 2R + 2R = 4R 1 R_ AB = 1 8R + 1 4R = 3 8R R_ AB = 8R 3