A battery of emf 12 V and negligible resistance is connected across the diagonally opposite corners of a cubical network consisting of 12 resistors each of resistance 2 . The equivalent resistance of the network is

Step-by-step solution

In a closed loop, say A B C C^ E A and apply Kirchhoffs second rule, -I R- ( I 2 ) R-I R+ =0 where, R is the resistance of each edge and the emf of battery. Thus, = 5 2 I R The equivalent resistance R_ eq of the network is R_ eq = 3 I = 5 6 R= 5 6 2= 5 3