Three bulbs of 40 ~W , 60 ~W , and 100 ~W are arranged in series with a 220 ~V source. The maximum light is obtained from

Step-by-step solution

The power consumed by a bulb is given by P = I^2 R , where I is the current flowing through the bulb and R is its resistance. Since the bulbs are connected in series, the same current I flows through all of them. The resistance R of a bulb is related to its rated power P_ rated and rated voltage V by the formula R = V^2 P_ rated . For the given bulbs: R₄₀ = V^2 40 R₆₀ = V^2 60 R₁₀₀ = V^2 100 Comparing the resistances, we find R₄₀ > R₆₀ > R₁₀₀ . Since P = I^2 R and I is constant for all bulbs in series, the power co