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COMEDK2024Morning ShiftPhysicsCurrent ElectricityActual

The resistance of the galvanometer and shunt of an ammeter are 90 ~ohm and 10 ~ohm respectively, then the fraction of the main current passing through the galvanometer and the shut respectively are:

Options

  1. A1 10 and 1 90
  2. B1 10 and 9 10
  3. C9 10 and 1 10
  4. D1 90 and 1 10

Correct answer

B. 1 10 and 9 10

Step-by-step solution

Let I be the total current, I_g be the current through the galvanometer, and I_s be the current through the shunt. Given the resistance of the galvanometer G = 90 , and the resistance of the shunt S = 10 , . Since the galvanometer and shunt are connected in parallel, the potential difference across them is the same: I_g G = I_s S I_g (90) = I_s (10) I_s = 9 I_g The total current I is given by I = I_g + I_s . Substituting I_s = 9 I_g into this equation: I = I_g + 9 I_g = 10 I_g The fraction of the main current passi

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