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COMEDK2022PhysicsCurrent Electricity

A cell of emf 2 ~V is connected with a load of resistance 1.5 . The power delivered by the cell to the load is maximum, then power transferred to the load is

Options

  1. A0.67 ~W
  2. B2.67 ~W
  3. C1.33 ~W
  4. D3.25 ~W

Correct answer

A. 0.67 ~W

Step-by-step solution

For maximum power transfer, internal resistance r = load resistance R . Since R = 1.5 , we have r = 1.5 . Maximum power delivered to load: P_ max = E^2 4R = (2)^2 4 1.5 = 4 6 = 2 3 0.67 W

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