Two electric bulbs A and B are rated as 60 ~W and 100 ~W . They are connected in parallel to the same source. Then,

Step-by-step solution

Given, power of bulb A, P_ A =60 ~W Power of bulb B, P_ B =100 ~W Since, both bulbs are connected to the same power source in parallel combination. Thus, P_ A = V² R_ A =60 ~W and P_ B = V² R_ B =100 ~W R_ A = V² 60 and R_ B = V² 100 Current in bulb A, I_ A = Potential Resistance I_ A = V V² I_ A = 60 V Similarly, current in bulb B, I_ B = V V² = 100 V It is clear that I_ B >I_ A .