The maximum current that can be measured by a galvanometer of resistance 40 is 10 ~mA . It is converted into a voltmeter that can read upto 50 ~V . The resistance to be connected in series with the galvanometer (in ohm) is

Step-by-step solution

Given, resistance of the galvanometer, G=40 Current in the galvanometer, l_ g =10 ~m ~A =10 10³ ~A Maximum reading of voltmeter, V=50 ~V The galvanometer can be converted into voltmeter by connecting a shunt resistance (S) in the series. Voltage in the voltmeter is given by aligned & & V &=I_ z (C+R) & & 50 &=10 10⁻³(40+R) & & 5000 &=40+R & & R &=4960 aligned