The current in a simple series circuit is 5.0 ~A . When an additional resistance of 2.0 is inserted, the current drops to 4.0 ~A . The original resistance of the circuit (in ) is

Step-by-step solution

Given, I₁=5 ~A , R₂=2 , I₂=4 ~A Let initial resistance be R . As voltage given is same in both cases, so aligned V₁ &=V₂ I₁ R &=I₂ R^ =I₂ (R+R₂ ) 5 R &=4 (R+2) R=8 aligned