In the circuit given E=6.0 ~V , R₁=100 ₂=R₃=50 and R₄=75 . The equivalent resistance of the circuit (in ) is

Step-by-step solution

Given, R₁=100 , R₂=R₃=50 , E=6 ~V , R₄=75 As R₂, R₃ and R₄ are in parallel combination, so their equivalent resistance be aligned 1 R^ &= 1 R₂ + 1 R₃ + 1 R₄ &= 1 50 + 1 50 + 1 75 = 3+3+2 150 = 8 150 aligned or R^ = 150 8 Now, R^ is in series with R₁ , so R_ net =R₁+R^ =100+ 150 8 = 950 8 =118.75