COMEDK2017PhysicsCurrent Electricity
In an ammeter 10 % of main current is passing through the galvanometer. If the resistance of the galvanometer is G , then the shunt resistance (in ) is
Options
- A9 G
- BG 9
- C90 G
- DG 90
Correct answer
B. G 9
Step-by-step solution
If I be the main current, then current passing through galvanometer, I_ g =10 % of I= I 10 Resistance of galvanometer, R_ g =G Shunt resistance, R_ S = I_ g R_ g I-I_ g = I 10 G I- I 10 = G 9