Effective capacitance between A and B in the figure shown is (all capacitances are in F )

Step-by-step solution

As it is a balanced Wheatstone bridge, so C and D are same potential and the capacitor 2 F is ineffective. The 3 F and 6 F in upper portion are in series, so equivalent capacitance, C₁= 3 6 3+6 = 18 9 =2 F Similarly, C₂= 4 8 4+8 = 32 12 = 8 3 F C₁ and C₂ are in parallel, so their equivalent capacitance C=C₁+C₂=2+ 8 3 = 14 3 F