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COMEDK2025PhysicsElectromagnetic InductionActual

In an AC generator, a rectangular coil having 400 turns, each having an area of 210 ~cm ^2 is rotated in a uniform magnetic field of magnitude 4 T . If the coil makes 480 revolutions in a minute, the maximum value of emf produced by the generator is:

Options

  1. A1096 V
  2. B1967 V
  3. C6918 V
  4. D1689 V

Correct answer

D. 1689 V

Step-by-step solution

The maximum induced emf in an AC generator is given by the formula _ max = N A B , where N is the number of turns, A is the area of the coil, B is the magnetic field strength, and is the angular velocity of the coil. Given values: N = 400 A = 210 cm ^2 = 210 10⁻⁴ m ^2 = 0.021 m ^2 B = 4 T Frequency f = 480 revolutions 60 seconds = 8 Hz The angular velocity is calculated as: = 2 f = 2 8 = 16 rad/s Substituting these values into the formula for _ max : _ max = 400 0.021 4 16 _ max = 33.6 16 _ max = 537.6 Using 3.1415

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