A circular coil of area 2 2 ~cm ^2 and resistance 2 is arranged vertically in the east -west direction. A uniform magnetic field 0.2 T is set up across the plane in the north to east direction. Now the magnetic field is removed at a steady rate in 0.4 s What is the current developed in the coil?

Step-by-step solution

The area of the coil is A = 2 2 cm ^2 = 2 2 10⁻⁴ m ^2 . The magnetic field B = 0.2 T is in the north-east direction, while the coil is in the east-west plane. The normal to the coil points in the north-south direction. The angle between the magnetic field (north-east) and the normal to the coil (north or south) is 45^ . The initial magnetic flux _i through the coil is given by _i = B A (45^ ) = 0.2 (2 2 10⁻⁴) 1 2 = 0.4 10⁻⁴ Wb . The final magnetic flux _f is 0 since the magnetic field is removed. The change in flux