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COMEDK2025PhysicsElectromagnetic InductionActual

A rectangular coil of 250 turns has an average area of 20 ~cm 15 ~cm . The coil rotates with a speed of 60 cycles per second in a uniform magnetic field of 2 10⁻² ~T about an axis perpendicular to the field. The peak value of the induced emf is:

Options

  1. A36 volt
  2. B18 volt
  3. C12 volt
  4. D30 volt

Correct answer

B. 18 volt

Step-by-step solution

The peak value of the induced electromotive force (emf) in a rotating coil is given by the formula ₀ = N A B , where N is the number of turns, A is the area of the coil, B is the magnetic field strength, and is the angular velocity. Given values: N = 250 A = 20 cm 15 cm = 0.2 m 0.15 m = 0.03 m ² B = 2 10⁻² T Frequency f = 60 Hz Angular velocity = 2 f = 2 60 = 120 rad/s Substituting these values into the formula: ₀ = 250 0.03 (2 10⁻²) 120 Calculating the product: ₀ = 250 0.03 0.02 120 ₀ = 7.5 0.02 120 ₀ = 0.15 120 ₀

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