The current in a coil changes steadily from 3 ~A to 5 ~A in 0.2 ~s when an emf of 2 V is induced in it. The self-inductance of the coil is

Step-by-step solution

The induced emf in a coil due to a change in current is given by the formula = L | di dt | , where L is the self-inductance of the coil. Given values are: Change in current i = 5 A - 3 A = 2 A Time interval t = 0.2 s Induced emf = 2 V = 2 10⁻⁶ V The rate of change of current is di dt = i t = 2 A 0.2 s = 10 A/s . Substituting these values into the formula: 2 10⁻⁶ V = L 10 A/s L = 2 10⁻⁶ 10 H L = 0.2 10⁻⁶ H = 0.2 H . Answer: 0.2 H