COMEDK2014PhysicsElectromagnetic Induction
An aeroplane is flying horizontally with a velocity of 360 ~km ~h ⁻¹ . The distance between the tips of the wings of the aeroplane is 50 ~m . The vertical component of the earth's magnetic field is 4 10⁻⁴ Wbm ⁻² . The induced emf is
Options
- A200 ~V
- B20 ~V
- C2 ~V
- D0.2 ~V
Correct answer
C. 2 ~V
Step-by-step solution
Given, velocity of aeroplane, aligned v &=360 kmh ⁻¹ &=360 5 18 ~ms ⁻¹=100 ~ms ⁻¹ aligned Distance between the tips of wings, l=50 ~m Vertical component of earth's magnetic field, aligned &B_ V =4 10⁻⁴ Wbm ⁻² & aligned Induced emf, e &=B_ V v l &=4 10⁻⁴ 100 50=2 ~V aligned aligned