A particle of mass 3 g and charge 60 C is released from rest in a uniform electric field of intensity 10^5 N C⁻¹ . If the value of kinetic energy attained by the particle after moving through a distance of 2 cm is m 10⁻² ~J , then the value of m is:

Step-by-step solution

Given mass m = 3 g = 3 10⁻³ kg , charge q = 60 C = 60 10⁻⁶ C , electric field E = 10^5 N C ⁻¹ , and distance d = 2 cm = 0.02 m . The force acting on the particle is F = qE = (60 10⁻⁶ C ) (10^5 N C ⁻¹) = 6 N . The work done by the electric field on the particle is W = F d = 6 N 0.02 m = 0.12 J . According to the work-energy theorem, the kinetic energy attained by the particle starting from rest is equal to the work done by the electric field. Kinetic Energy K = 0.12 J = 12 10⁻² J . Comparing this with the given expr