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COMEDK2024PhysicsElectrostatics

A charge q is enclosed by an imaginary Gaussian surface. If the radius of Gaussian surface is increasing at a rate d r d t = , then flux linked with surface is

Options

  1. Aincreasing at a rate, d d t =
  2. Bdecreasing at a rate, d d t =-
  3. Cdecreasing at a rate, d d t = 1 k
  4. Dq ₀

Correct answer

D. q ₀

Step-by-step solution

Electric flux coming out from a surface does not depend on its surface area. It depends only on charge enclosed by surface. As, flux, = q ₀

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