Two unlike charges of the same magnitude Q are placed at a distance d . The intensity of the electric field at the middle point is the line joining the two charges is

Step-by-step solution

The magnitude of electric field due to charge at point A is E_A=| E |= 1 4 ₀ Q ( d 2 )^2 = 1 4 ₀ 4 Q d^2 Similarly, E_B=| E |= 1 4 ₀ Q ( d 2 )^2 = 1 4 ₀ 4 Q d^2 From figure, it is clear that E_A and E_B are in same direction, hence. Net electric field, aligned & E=E_A+E_B=2| E |=2 1 4 ₀ 4 Q d^2 & E= 1 4 ₀ 8 Q d^2 aligned