COMEDK2024Evening ShiftPhysicsElectrostaticsActual
Three point charges are located on a circular arc at A, B and C as shown in the figure below. The total electric field at the centre of the arc (0) is
Options
- A15000 ~NC ⁻¹
- B5000 ~NC ⁻¹
- C20000 ~NC ⁻¹
- D10000 ~N C ⁻¹
Correct answer
B. 5000 ~NC ⁻¹
Step-by-step solution
r = 6.0 cm = 0.06 m, r^2 = 0.0036 m ^2 E_A = E_B = (9 10^9)(4.0 10⁻⁹) 0.0036 = 10000 N/C (away from A and B) E_C = (9 10^9)(2.0 10⁻⁹) 0.0036 = 5000 N/C (towards C, since charge is negative) By symmetry, A and B are 60° on either side of OC axis. Their perpendicular components cancel. Only components along OC axis are considered: E_ net = E_C - E_A 60° - E_B 60° = 5000 - 10000(0.5) - 10000(0.5) = 5000 - 5000 - 5000 = -5000 N/C Magnitude = 5000 NC ⁻¹