Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
COMEDK2019PhysicsElectrostatics

An electron is accelerated through a potential difference of 45.5 ~V . The velocity acquired by it (in ms ⁻¹ ) is

Options

  1. A4 10⁶
  2. B4 10⁴
  3. C10⁶
  4. Dzero

Correct answer

A. 4 10⁶

Step-by-step solution

Given, potential difference, V=45.5 ~V Velocity, v= ? Energy acquired by the electron after getling accelerated through the potential difference V is eV , which is equal to its kinetic energy. Hence, kinetic energy ( KE )= 1 2 m_ e v²=e V v= 2 e V m_ e [where, m_ e = mass of electron] Substituting the given values, we get aligned v &= 2 1.6 10⁻¹⁹ 45.4 9.11 10⁻³¹ &= 16 10¹² =4 10⁶ ~ms ⁻¹ aligned ###0

Practice Electrostatics on Quantrex Academy →

More from Electrostatics

A charge of 5 C is placed at the centre of a spherical shell S₁ of radius 10 cm. Now this system is enclosed inside another spherical shell S₂ of radius 20 cm. The ratio of the ele 2026Two point charges P = +25 C and Q = -16 C are placed 5 cm apart. Find the position of the point at which the resultant electric field is zero: 2026Bodies P, Q, R, S are labelled as having charges Q_P = 0.5 10⁻¹⁹C , Q_Q = 0.7 10⁻¹⁹C , Q_R = 2.1 10⁻¹⁹C , Q_S = 4.8 10⁻¹⁹C respectively. Select the body having the correct charge. 2026Uniform electric field of 5 10^3 ,NC⁻¹ is maintained in the positive Y direction. Now a point charge of 2 10⁻⁴C at rest is released from the origin. The kinetic energy attained by 2026A pith ball of mass 'm' gram and charge 'Q' is suspended using a mass less silk thread near a large charged conducting metal sheet of area 'A' and surface charged density ' '. If t 2026In a uniform electric field 10^6 N C⁻¹ an electric dipole of length 4 cm is placed with its axis making an angle 60^ with the electric field. If the dipole experiences a torque of 2026An electric field and magnetic field 1.8 10^4 Vm⁻¹ and 6 10⁻³ T respectively are applied simultaneously on an electron beam such that path of the beam remains undeviated, then the 2026A uniform electric field E = 3 i + 6 j + k passes through a closed cuboidal surface. One face of the cuboid has an area 4 m^2 and an outward unit normal given by 2 i +2 j +3 k 17 . 2026 Full Electrostatics list All COMEDK PYQs