COMEDK2016PhysicsElectrostatics
Potential energy of 2 charge 10 nC each separated by a distance of 0.09 ~m in air is
Options
- A10 J
- B1 ~mJ
- C10 ~mJ
- D10 ~J
Correct answer
A. 10 J
Step-by-step solution
Given q₁=q₂=10 nC =10 10⁻⁹ C r=0.09 ~m Potential energy of two point charges is given by aligned U &= 1 4 ₀ q₁ q₂ r &=9 10⁹ 10 10⁻⁹ 10 10⁻⁹ 0.09 =10⁻⁵ ~J &=10 J aligned