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IAT IISER2023PhysicsCurrent Electricity

A current I flows through a cylindrical cable of length L and uniform cross-sectional area A . The power dissipated due to the current is P₁ . The cable is cut into two equal halves. If the cross-sectional area and the current flowing through the two halves remain unchanged and the power dissipated in each half is P₂ , which of the following options is correct?

Options

  1. AP₂=P₁
  2. BP₂=2 P₁
  3. CP₂=P₁ / 4
  4. DP₂=P₁ / 2

Correct answer

D. P₂=P₁ / 2

Step-by-step solution

No solution available.

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