In the following reaction sequence, major products X and Y are acyclic monomers. 500 mol of X completely reacts with 500 mol of Y to give 1 mol of a single biodegradable acyclic copolymer Z as the only product. The amount of Z formed in grams is ____. Given: Atomic mass (in amu): H : 1 , C : 12 , N : 14 , O : 16 , Br : 80

Step-by-step solution

Identification of monomer X The given reaction sequence for X is: CH ₃ I KCN CH ₃ CN CH ₃ CN H ₃ O ^+, CH ₃ COOH CH ₃ COOH Red P, Br ₂ BrCH ₂ COOH (Hell-Volhard-Zelinsky reaction) BrCH ₂ COOH NH ₃ (excess) H ₂ N - CH ₂- COOH Thus, X is Glycine. Molar mass of X ( C ₂ H ₅ NO ₂ ) = 2(12) + 5(1) + 14 + 2(16) = 75 g/mol . Identification of monomer Y Caprolactam on acidic hydrolysis gives -aminocaproic acid: Caprolactam H ₃ O ^+, H ₂ N -( CH ₂)₅- COOH Thus, Y is -aminocaproic acid. Molar mass of Y ( C ₆ H ₁₃ NO ₂ ) = 6(1