Paragraph: Thermal decomposition of gaseous X ₂ to gaseous X at 298 ~K takes place according to the following equation: X ₂( ~g ) 2 X ( g ) The standard reaction Gibbs energy, _ r G^ , of this reaction is positive. At the start of the reaction, there is one mole of X ₂ and no X . As the reaction proceeds, the number of moles of X formed is given by . Thus, _ equilibrium is the number of moles of X formed at equilibri

Step-by-step solution

A] On decreasing P T Q = n x 2   P T n x 2   n T Q will be less than K p reaction will move in forward direction B] At the start of the reaction ∆ G = ∆ G o + R T ln Q t = 0 ,   Q = 0 ⇒ ∆ r x n G =   – v e   ( s p o n t a n e o u s ) C] If β e q u i l i b r i u m = 0.7 K p = 8 × 0.49 4 - 0.49 = 3.92 3.51 K p > 1 Since it is given that ∆ G o > 0 ⇒ K p < 1 ∴ This is incorrect D] K p = K C × R T ∆ n g K C = K p R