Consider the following reactions in which all the reactants and products are present in gaseous state 2xy x₂ + y₂ K₁ = 2.5 10^5 xy + 1 2 z₂ xyz K₂ = 5 10⁻³ The value of K₃ for the equilibrium 1 2 x₂ + 1 2 y₂ + 1 2 z₂ xyz is:

Step-by-step solution

The given reactions are: 2xy x₂ + y₂ K₁ = 2.5 10^5 xy + 1 2 z₂ xyz K₂ = 5 10⁻³ We need to find the equilibrium constant K₃ for the reaction: 1 2 x₂ + 1 2 y₂ + 1 2 z₂ xyz Reversing the first reaction and multiplying it by 1 2 , we get: 1 2 x₂ + 1 2 y₂ xy The equilibrium constant for this modified reaction is: K' = ( 1 K₁ )^ 1 2 = 1 K₁ Adding this modified reaction to the second reaction: 1 2 x₂ + 1 2 y₂ xy (K') xy + 1 2 z₂ xyz (K₂) --------------------------------------------------- 1 2 x₂ + 1 2 y₂ + 1 2 z₂ xyz The