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JEE Main20268 April 2026Evening ShiftChemistryChemical EquilibriumActual

Solid carbon, CaO and CaCO₃ are mixed and allowed to attain equilibrium at T K. CaCO ₃(s) CaO (s) + CO ₂(g) K_ p₁ = 0.08 atm C (s) + CO ₂(g) 2 CO (g) K_ p₂ = 2 atm The partial pressure of CO is ________ 10⁻¹ atm

Correct answer

0

Step-by-step solution

For the first equilibrium: CaCO ₃(s) CaO (s) + CO ₂(g) K_ p₁ = P_ CO ₂ = 0.08 atm For the second equilibrium: C (s) + CO ₂(g) 2 CO (g) K_ p₂ = (P_ CO )^2 P_ CO ₂ = 2 atm Substituting the value of P_ CO ₂ : (P_ CO )^2 0.08 = 2 (P_ CO )^2 = 0.16 P_ CO = 0.4 atm = 4 10⁻¹ atm Answer: 4

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