Match the reactions in List-I with the features of their products in List-II and choose the correct option. List I List II ( P ) - - 1 - Bromo - 2 - ethylpentane ( Single   enantiomer )     → S N   2     reaction aq .  NaOH 1 Inversion of configuration ( Q ) - - 2 - Bromopentane Single   Enantiomer     → S N   2   reaction aq .  NaOH  

Step-by-step solution

1 - Bromo - 2 - ethylpentane ( Single   enantiomer )     → S N   2     reaction aq .  NaOH 2 - ethylpentanol In the above reaction the chiral carbon is not involving in the reaction as S N 2 reaction takes place via formation of transition state but not through formation of intermediate. In the above reaction, bromine attached to chiral carbon, and it is involving in S N 2 reaction. Hence, the alcohol formed in inversion configuration. The substrate is undergoing S N 1 react