JEE Advanced 2018Paper 2
- Exam
- JEE Advanced
- Year
- 2018
- Paper
- Paper 2
- Subject
- Chemistry
- Chapter
- Haloalkanes and Haloarenes
JEE Advanced 2018 · Paper 2 · Chemistry · Haloalkanes and Haloarenes
LIST-I contains reactions and LIST-II contains major products...
LIST-I contains reactions and LIST-II contains major products
| LIST-I | LIST -II | ||
| A) | P) | ||
| B) | Q) | ||
| C) | R) | ||
| D) | S) | ||
| T) |
Match each reaction in LIST-I with one or more products in LIST-II and choose the correct option
Options
- Aa-s,t;b-s;c-q,r;d-q,r,s;
- Ba-r,s,t;b-r;c-s,t;d-s,t;
- Ca-p,s;b-q;c-s;d-r;
- Da-q;b-s,t;c-r;d-t;
Correct answer
C. a-p,s;b-q;c-s;d-r;
Step-by-step solution
Bulky base is present, it will abstract proton, hence will undergo E2 reaction

Hydrogen ion will protonate the oxygen of methoxy group and make it a good leaving group, hence methanol and t-butyl bromide is formed.

Methoxy group will abstract proton. E2 elimination occur

It will undergo mechanism.

Hydrogen ion will protonate the oxygen of methoxy group and make it a good leaving group, hence methanol and t-butyl bromide is formed.
Methoxy group will abstract proton. E2 elimination occur
It will undergo mechanism.