JEE Advanced 2017Paper 2
- Exam
- JEE Advanced
- Year
- 2017
- Paper
- Paper 2
- Subject
- Chemistry
- Chapter
- Haloalkanes and Haloarenes
JEE Advanced 2017 · Paper 2 · Chemistry · Haloalkanes and Haloarenes
Paragraph: The reaction of compound P with CH_ 3 MgBr (excess) in...
Paragraph:
The reaction of compound with (excess) in \left(\mathrm{C}_{2} \mathrm{H}_{5}\right)_{2} \mathrm{O}\mathrm{H}_{2} \mathrm{O}\mathbf{Q}\mathbf{Q}\mathrm{H}_{2} \mathrm{SO}_{4}0^{\circ} \mathrm{C}\mathbf{R}\mathbf{R}\mathrm{CH}_{3} \mathrm{COCl}\mathrm{AlCl}_{3} in \mathrm{CH}_{2} \mathrm{Cl}_{2}\mathrm{H}_{2} \mathrm{O}\mathbf{S}\mathbf{P}\mathbf{Q} to \mathbf{R} and \mathbf{R} to \mathbf{S}, are
Options
- ADehydration and Friedel-Crafts acylation
- BFriedel-Crafts alkylation, dehydration, and Friedel-Crafts acylation
- CAromatic sulfonation and Friedel-Crafts acylation
- DFriedel-Crafts alkylation and Friedel-Crafts acylation
Correct answer
D. Friedel-Crafts alkylation and Friedel-Crafts acylation
Step-by-step solution
The reaction of an ester (other than format) with Grignard’s reagent followed by hydrolysis in acidic medium produces a tertiary alcohol.
The dehydration of -alcohol at in the given compound produces an alkyl group in the benzene ring. This compound on reaction with in and shows Friedel craft's alkylation reaction