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JEE Advanced 2011Paper 1
Exam
JEE Advanced
Year
2011
Paper
Paper 1
Subject
Chemistry
Chapter
Hydrocarbons

JEE Advanced 2011 · Paper 1 · Chemistry · Hydrocarbons

The total number of alkenes possible by dehydrobromination of...

The total number of alkenes possible by dehydrobromination of 3-bromo-3-cyclopentylhexane using alcoholic KOH\mathrm{KOH} isThe total number of alkenes possible by dehydrobromination of 3-bromo-3-cyclopentylhexane using alcoholic KOH is

Correct answer

5

Step-by-step solution

The substrate has three different types of B−H\mathrm{B}-\mathrm{H}, therefore, first, three structural isomers of alkenes are expected as The total number of alkenes possible by dehydrobromination of 3-bromo-3-cyclopentylhexane using alcoholic KOH is
The last two alkenes II and III are also capable of showing geometrical isomerism hence two geometrical isomers for each of them will be counted giving a total of five isomers.
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