The synthesis of 3-octyne is achieved by adding a bromoalkane into...

The synthesis of 3-octyne is achieved by adding a bromoalkane into a mixture of sodium amide and an alkyne. The bromoalkane and alkyne respectively are

Options

A $\mathrm{BrCH}_2 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CH}_3$ and $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{C} \equiv \mathrm{CH}$
B $\mathrm{BrCH}_2 \mathrm{CH}_2 \mathrm{CH}_3$ and $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{C} \equiv \mathrm{CH}$
C $\mathrm{BrCH}_2 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CH}_3$ and $\mathrm{CH}_3 \mathrm{C} \equiv \equiv \mathrm{CH}$
D $\mathrm{BrCH}_2 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CH}_3$ and $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{C} \equiv \mathrm{CH}$ a)

Correct answer

D. $\mathrm{BrCH}_2 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CH}_3$ and $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{C} \equiv \mathrm{CH}$ a)

Step-by-step solution

\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{C} \equiv \mathrm{C}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}_3

There are two (marked) possibility of halides Thus, in the given context

\begin{array}{r}\mathrm{CH}_{3}\mathrm{CH}_{2}\mathrm{C} \equiv \mathrm{CH}+\mathrm{NaNH}_{2} \longrightarrow \\ \mathrm{CH}_{3}\mathrm{CH}_{2}-\mathrm{C} \equiv \overline{\mathrm{CNa}^{+}} \end{array}

$\begin{aligned} \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{C} \equiv \overline{\mathrm{CNa}}\\ \longrightarrow \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{C} \equiv \mathrm{BrCH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3} \\ \text{ 3-octyne } \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3} \end{aligned}

Hydrocarbon Conceptual,$ reaction understanding II

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