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JEE Advanced2025ChemistryIonic EquilibriumActual

The solubility of barium iodate in an aqueous solution prepared by mixing 200 mL of 0.010 M barium nitrate with 100 mL of 0.10 M sodium iodate is X 10⁻⁶ ~mol dm ⁻³ . The value of X is . Use: Solubility product constant (K_ sp ) of barium iodate =1.58 10⁻⁹

Correct answer

0

Step-by-step solution

[ NaIO ₃ ]= 6 300 =2 10⁻² M aligned Ba ( IO ₃ )₂( ~s ) Ba ²⁺+ & 2 IO ₃⁻ s & (2 10⁻²+2 ~s ) aligned aligned & K _ sp = [ Ba ⁺² ] [ IO ₃⁻ ]^2 & 1.58 10⁻⁹= [ Ba ⁺² ] (2 10⁻² )^2 & [ Ba ⁺² ]= s =3.95 10⁻⁶ M & X =3.95 aligned

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