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JEE Advanced 2024Paper 2
Exam
JEE Advanced
Year
2024
Paper
Paper 2
Subject
Chemistry
Chapter
Redox Reactions

JEE Advanced 2024 · Paper 2 · Chemistry · Redox Reactions

In a metal deficient oxide sample, M_ x Y_2 O_4 ( M and Y are...

In a metal deficient oxide sample, MxY2O4\mathbf{M}_{\mathbf{x}} \mathbf{Y}_2 \mathbf{O}_4 ( M\mathbf{M} and Y\mathbf{Y} are metals), M\mathbf{M} is present in both +2 and +3 oxidation states and Y\mathbf{Y} is in +3 oxidation state. If the fraction of M2+\mathbf{M}^{2+} ions present in M\mathbf{M} is 13\frac{1}{3}, the value of X\mathbf{X} is ________.

Options

  1. A0.25
  2. B0.33
  3. C0.67
  4. D0.75

Correct answer

D. 0.75

Step-by-step solution

Average oxidation state of M=13×2+23×3=+83\mathrm{M}=\frac{1}{3} \times 2+\frac{2}{3} \times 3=+\frac{8}{3}∴ For MXM2Y483×x+3×2+4(−2)=083×x=2x=34=0.75\begin{aligned} & \therefore \text{ For } \mathrm{M}_{\mathrm{X}} \mathrm{M}_{2} \mathrm{Y}_4 \\ & \frac{8}{3} \times \mathrm{x}+3 \times 2+4(-2)=0 \\ & \frac{8}{3} \times \mathrm{x}=2 \\ & \mathrm{x}=\frac{3}{4}=0.75\end{aligned}$$
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