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JEE Advanced 2020Paper 2
Exam
JEE Advanced
Year
2020
Paper
Paper 2
Subject
Chemistry
Chapter
Redox Reactions

JEE Advanced 2020 · Paper 2 · Chemistry · Redox Reactions

Choose the correct statement(s) among the following.

Choose the correct statement(s) among the following.

Options

  1. ASnCl2⋅2H2O{SnCl}_{2} \cdot 2{H}_{2}O is a reducing agent.
  2. B{SnO}_{2}reactswithreacts withKOHtoformto form{K}_{2}\left[Sn ( OH{)}_{6}\right]
  3. CA solution of PbCl2{PbCl}_{2} in HClHCl contains Pb2+{Pb}^{2 +}and Cl−{Cl}^{-} ions.
  4. DThe reaction of Pb3O4{Pb}_{3}{O}_{4} with hot dilute nitric acid to give PbO2{PbO}_{2} is a redox reaction.

Correct answer

A. SnCl2⋅2H2O{SnCl}_{2} \cdot 2{H}_{2}O is a reducing agent.

Step-by-step solution

(A) Sn2+{Sn}^{2 +} is a good reducing agent which gets oxidise into Sn4+{Sn}^{4 +}

(B) Amphoteric nature.

(C) PbCl2+2Cl−⟶[PbCl4]2−{PbCl}_{2} + 2{Cl}^{-} ⟶ {\left[{PbCl}_{4}\right]}^{2 -}

(D) Pb3O4(2PbO+PbO2)+4HNO3(Conc.)→PbO2↓+2Pb(NO3)2+6H2O\mathop{{Pb}_{3}{O}_{4}}_{( 2PbO + {PbO}_{2} )} + \mathop{4{HNO}_{3}}_{( Conc . )} \to {PbO}_{2} ↓ + 2Pb{\left({NO}_{3}\right)}_{2} + 6{H}_{2}O

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