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JEE Advanced 2024Paper 2
Exam
JEE Advanced
Year
2024
Paper
Paper 2
Subject
Chemistry
Chapter
Solutions

JEE Advanced 2024 · Paper 2 · Chemistry · Solutions

Vessel-1 contains w_2 ~g of a non-volatile solute X dissolved in...

Vessel-1 contains w2 g\mathbf{w}_2 \mathrm{~g} of a non-volatile solute X\mathbf{X} dissolved in w1 g\mathbf{w}_1 \mathrm{~g} of water. Vessel- 2 contains w2 g\mathbf{w}_2 \mathrm{~g} of another non-volatile solute Y\mathbf{Y} dissolved in w1 g\mathbf{w}_1 \mathrm{~g} of water. Both the vessels are at the same temperature and pressure. The molar mass of X\mathbf{X} is 80%80 \% of that of Y\mathbf{Y}. The van't Hoff factor for X\mathbf{X} is 1.2 times of that of Y\mathbf{Y} for their respective concentrations. The elevation of boiling point for solution in Vessel-1 is ________. %\% of the solution in Vessel-2.

Correct answer

0

Step-by-step solution

Vessel-I (\left(\Delta \mathrm{T}_{\mathrm{b}}\right)_{I\mathrm{I}}=\mathrm{i}_{\mathrm{x}} \frac{\mathrm{w}_2}{\mathrm{M}_{\mathrm{x}}} \cdot \frac{1}{\mathrm{w}_1} \times 1000 \times \mathrm{K}_{\mathrm{b}}) (\mathrm{M}_{\mathrm{X}}=) Molar mass of ' X ' Vessel-II (\left(\Delta \mathrm{T}_{\mathrm{b}}\right)_{II\mathrm{II}}=\mathrm{i}_{\mathrm{Y}} \frac{\mathrm{w}_2}{\mathrm{M}_{\mathrm{Y}}} \cdot \frac{1}{\mathrm{w}_1} \times 1000 \times \mathrm{K}_{\mathrm{b}}) MY=M_Y= Molar mass of ' YY ' (ΔTb)I(ΔTb)II×100=ixiY⋅MYMx×100=1.2×10080×100=150%\begin{aligned} & \frac{\left(\Delta T_b\right)_{\mathrm{I}}}{\left(\Delta \mathrm{T}_{\mathrm{b}}\right)_{\mathrm{II}}} \times 100=\frac{\mathrm{i}_{\mathrm{x}}}{\mathrm{i}_{\mathrm{Y}}} \cdot \frac{\mathrm{M}_{\mathrm{Y}}}{\mathrm{M}_{\mathrm{x}}} \times 100 \\ & =1.2 \times \frac{100}{80} \times 100 \\ & =150 \% \end{aligned})$
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