JEE Advanced 2021Paper 1
- Exam
- JEE Advanced
- Year
- 2021
- Paper
- Paper 1
- Subject
- Chemistry
- Chapter
- Solutions
JEE Advanced 2021 · Paper 1 · Chemistry · Solutions
The boiling point of water in a 0.1 molal silver nitrate solution...
The boiling point of water in a molal silver nitrate solution (solution ) is . To this solution , an equal volume of molal aqueous barium chloride solution is added to make a new solution B. The difference in the boiling points of water in the two solutions is .
(Assume: Densities of the solutions are the same as that of water and the soluble salts dissociate completely.
Use: Molal elevation constant (Ebullioscopic Constant), ; Boiling point of pure water as .)
The value of \left|y\right| is ___.
(Assume: Densities of the solutions are the same as that of water and the soluble salts dissociate completely.
Use: Molal elevation constant (Ebullioscopic Constant), ; Boiling point of pure water as .)
The value of \left|y\right| is ___.
Correct answer
0
Step-by-step solution
After adding solution in solution will be precipitate.
Since volume of both solutions are equal let's take
of each.
so initial moles of
initial moles of
New
\left(\dfrac{3 \times 0 .05}{2} + \dfrac{3 \times 0 .05}{2}\right) \times 0 .5 = 0{.075}^{∘}C= {\Delta T}_{{b}_{1}} - {\Delta T}_{{b}_{2}} = 0 .1 - 0 .075= 0 .025 = 2 .5 \times {10}^{- 2} K