For a solution formed by mixing liquids L and M , the vapour pressure of L plotted against the mole fraction of M in solution is shown in the following figure, Here, X _ L and X _ M represent mole fractions of L and M

JEE Advanced 2017Paper 1

Exam: JEE Advanced
Year: 2017
Paper: Paper 1
Subject: Chemistry
Chapter: Solutions

JEE Advanced 2017 · Paper 1 · Chemistry · Solutions

For a solution formed by mixing liquids L and M , the vapour...

For a solution formed by mixing liquids $\text{L}$ and $\text{M}$ , the vapour pressure of $\text{L}$ plotted against the mole fraction of $\text{M}$ in solution is shown in the following figure, Here, ${X}_{L}$ and ${X}_{M}$ represent mole fractions of $\text{L}$ and $\text{M}$ , respectively, in the solution. The correct statement(s) applicable to this system is(are) -
$For a solution formed by mixing liquids L and M , the vapour pressure of L plotted against the mole fraction of M in$

Options

AThe point Z represents vapour pressure of pure liquid M and Raoult's law is obeyed when X_L $\to 0$
BThe point Z represents vapour pressure of pure liquid L and Raoult's law is obeyed when X_L $\to 1$
CAttractive inter-molecular interactions between $L – L$ in pure liquid L and M-M in pure liquid M are stronger than those between $L – M$ when mixed in solution
DThe point Z represents vapour pressure of pure liquid M and Raoult's law is obeyed from ${X}_{L} = 0$ to ${X}_{L} = 1$

Correct answer

B. The point Z represents vapour pressure of pure liquid L and Raoult's law is obeyed when X_L $\to 1$

Step-by-step solution

$For a solution formed by mixing liquids L and M , the vapour pressure of L plotted against the mole fraction of M in$

(iii) This is case of positive deviation hence

${\text{F}}_{\text{L} - \text{L}}, {\text{F}}_{\text{M} - \text{M}} > {\text{F}}_{\text{L} - \text{M}}$

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