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JEE Advanced2014MathematicsApplication of DerivativesActual

The slope of the tangent to the curve y - x 5 2 = x 1 + x 2 2 at the point (1, 3) is ________.

Correct answer

0

Step-by-step solution

2 y - x 5 d y d x - 5 x 4 = 1 1 + x 2 2 + x 2 1 + x 2 2 x Now put x = 1 , y = 3 and d y d x = m . 2 3 - 1 m - 5 = 1 4 + 1 4 2 m - 5 = 12 4 m = 5 + 3 = 8 d y d x = m = 8 .

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