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JEE Advanced2024MathematicsArea Under CurvesActual

Let S= (x, y) R R : x 0, y 0, y^2 4 x, y^2 12-2 x . and .3 y+ 8 x 5 8 . If the area of the region S is 2 , then is equal to

Options

  1. A17 2
  2. B17 3
  3. C17 4
  4. D17 5

Correct answer

B. 17 3

Step-by-step solution

Point of intersection of all curves is (2,2 2 ) Area = A ₁+ A ₂ 2 = ₀^2 2 x dx + 1 2 3 2 2 aligned & 2 =2 [ x^ 3 2 3 2 ]₀^2+3 2 & 2 = 17 2 3 & = 17 3 aligned

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