Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Advanced2022MathematicsArea Under CurvesActual

Consider the functions f , g : ℝ → ℝ defined by f x = x 2 + 5 12 and g x = 2 1 - 4 x 3 , x ≤ 3 4 , 0 , x > 3 4 If α is the area of the region x , y ∈ ℝ × ℝ : x ≤ 3 4 , 0 ≤ y ≤ min f x , g x , then the value of 9 α is _____ .

Correct answer

0

Step-by-step solution

Plotting the diagram of the given function we have, Now by diagram we can see twice of A 1 and A 2 will be the required area, So, required area = 2 · A 1 + A 2 ⇒ α = ∫ 0 1 2 x 2 + 5 12 d x + 1 2 3 4 - 1 2 · 2 3 × 2 ⇒ α = x 3 3 + 5 x 12 0 1 2 + 1 2 ⋅ 1 4 ⋅ 2 3 × 2 ⇒    α = 1 4 + 1 12 × 2 ⇒    α = 2 3 ⇒ 9 α = 6

Practice Area Under Curves on Quantrex Academy →

More from Area Under Curves

Passage: Consider the curve C₁ given by y = e^ -x for x [0, 10 ] , and the curve C₂ given by y = e^ -x ( x + x) for x [0, 10 ] . Let n be the total number of points of intersection 2026Passage: Consider the ellipses given by x^2 + 4y^2 = 1 and 4x^2 + y^2 = 1 . Question: If is the area of the common region that lies inside both the given ellipses, then the value o 2026The area of the region (x, y) : x^2 - 8x y -x is : 2026The area of the region (x, y) : 0 y 6 - x, y^2 4x - 3, x 0 is: 2026The area of the region R = (x, y): xy 27, 1 y x^2 is equal to: 2026The area of the region bounded by the curves x+3y^2=0 and x+4y^2=1 is equal to: 2026The area of the region (x, y): y - |x|, y |x x|, y 0 is: 2026If the area of the region bounded by 16x^2 - 9y^2 = 144 and 8x - 3y = 24 is A, then 3(A + 6 _e(3)) is equal to _______. 2026 Full Area Under Curves list All JEE Advanced PYQs