JEE Advanced 2013Paper 1
- Exam
- JEE Advanced
- Year
- 2013
- Paper
- Paper 1
- Subject
- Mathematics
- Chapter
- Area Under Curves
JEE Advanced 2013 · Paper 1 · Mathematics · Area Under Curves
The area enclosed by the curves y = x + x and y = |cos x - sin x|...
The area enclosed by the curves \text{y} = \left|\text{cos x} - \text{sin x}\right| is
Options
- A
- B
- C
- D
Correct answer
B.
Step-by-step solution
The given curves are
{\text{y}}_{1} = \text{sin x} + \text{cos x} = \sqrt{2} \text\sin \left(\text{x} + \dfrac{\pi}{4}\right)
{\text{y}}_{2} = \sqrt{2} | \text\sin \left(\dfrac{\pi}{4} - \text{x}\right) |
So, Required Area
.