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JEE Advanced 2018Paper 1
Exam
JEE Advanced
Year
2018
Paper
Paper 1
Subject
Mathematics
Chapter
Complex Number

JEE Advanced 2018 · Paper 1 · Mathematics · Complex Number

For a non-zero complex number z , let arg ( z ) denote the...

For a non-zero complex number zz, let arg(z)( z ) denote the principal argument with −π<arg(z)≤π- \pi < arg\left(z\right) \le \pi then, which of the following statement(s) is (are) FALSE?

Options

  1. AArg(−1−i)=π4,wherei=−1\left(- 1 - i\right) = \dfrac{\pi}{4}, wherei = \sqrt{- 1}
  2. BThe function f:R→f: \mathbb{R} \to\left(- \pi, \pi\right]definedbydefined byf\left(t\right) = arg\left(- 1 + it\right)forallt \in \mathbb{R},iscontinuousatallpointsof, is continuous at all points of\mathbb{R}, wherei = \sqrt{- 1}
  3. CFor any two non-zero complex numbers z1andz2{z}_{1}and{z}_{2} , argarg\left(\dfrac{{z}_{1}}{{z}_{2}}\right) - arg\left({z}_{1}\right) + arg\left({z}_{2}\right)isanintegermultipleofis an integer multiple of2\pi
  4. DFor any three given distinct complex numbers z1,z2andz3{z}_{1}, {z}_{2}and{z}_{3} , the locus of the point zz satisfying the condition arg((z−z1)(z2−z3)(z−z3)(z2−z1))=π\text{a}\text{r}\text{g}\left(\dfrac{\left(z - {z}_{1}\right)\left({z}_{2} - {z}_{3}\right)}{\left(z - {z}_{3}\right)\left({z}_{2} - {z}_{1}\right)}\right) = \pi lies on a straight line

Correct answer

A. Arg(−1−i)=π4,wherei=−1\left(- 1 - i\right) = \dfrac{\pi}{4}, wherei = \sqrt{- 1}

Step-by-step solution

\left(A\right) Arg\left(- 1 - i\right) = - \dfrac{3\pi}{4}<br/>(B)<br />\left(B\right) Arg\left(- 1 + it\right) = \left\{{π−tan⁡−1(t),t≥0−π+tan⁡−1(t),t<0\begin{cases}\pi - \tan^{- 1} \left(t\right), & t \ge 0 \\ - \pi + \tan^{- 1} \left(t\right), & t < 0\end{cases}\right)
Discontinuous at t=0t = 0
(C)arg(z1z2)−arg(z1)+arg(z2)( C ) arg\left(\dfrac{{z}_{1}}{{z}_{2}}\right) - arg\left({z}_{1}\right) + arg\left({z}_{2}\right)
=argz1−arg(z2)−arg(z1)+arg(z2)=0= arg{z}_{1} - arg\left({z}_{2}\right) - arg\left({z}_{1}\right) + arg\left({z}_{2}\right) =0
\left(D\right) arg\left(\dfrac{\left(z - {z}_{1}\right)\left({z}_{2} - {z}_{3}\right)}{\left(z - {z}_{3}\right)\left({z}_{2} - {z}_{1}\right)}\right) = \pi
⇒(z−z1)(z2−z3)(z−z3)(z2−z1)⇒ \dfrac{\left(z - {z}_{1}\right)\left({z}_{2} - {z}_{3}\right)}{\left(z - {z}_{3}\right)\left({z}_{2} - {z}_{1}\right)} is real
⇒z,z1,z2,z3⇒ z, {z}_{1}, {z}_{2}, {z}_{3} are concyclic
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