Consider the 6 × 6 square in the figure. Let A 1 , A 2 , … , A 49 be the points of intersections (dots in the picture) in some order. We say that A i and A j are friends if they are adjacent along a row or along a column. Assume that each point A i has an equal chance of being chosen. (There are two questions based on PARAGRAPH " II " , the question given below is one of them) Let p i be the probab

Step-by-step solution

Plotting the diagram of the given data we get, Now from above diagram we get, Number of points having 0 friend = 0 Number of points having 1 friend = 0 Number of points having 2 friends = 4 Number of points having 3 friends = 5 × 4 = 20 Number of points having 4 friends = 49 - 24 = 25 So, probability distribution table will be, Now from above table expected value will be given by, 7 · E X = 7 0 + 0 + 4 49 × 2 + 20 49 × 3 + 25 49 × 4 ⇒ 7 · E X = 7 100 + 60 + 8 49 ⇒ 7 ·