Suppose that Box-I contains 8 red, 3 blue and 5 green balls, Box-ll contains 24 red, 9 blue and 15 green balls, Box-III contains 1 blue, 12 green and 3 yellow balls, Box-IV contains 10 green, 16 orange and 6 white balls. A ball is chosen randomly from Box-l; call this ball b . If b is red then a ball is chosen randomly from Box-ll, if b is blue then a ball is chosen randomly from Box-III, and if b is green then a bal

Step-by-step solution

P Red from Box   I = 8 16 = 1 2 P Blue from Box   I = 3 16 P Green from Box   I = 10 32 = 5 16 Now, P Green from Box   II = 15 48 P Green from Box   III = 12 16 = 3 4 P White from Box   IV = 6 32 = 3 16 Event A : One of the chosen ball is white B : At least one of the chosen ball is green P A B = P A ∩ B P B = 5 16 × 3 16 1 2 × 15 48 + 3 16 × 3 4 + 5 16 × 1 = 5 52