- Exam
- JEE Advanced
- Year
- 2015
- Paper
- Paper 1
- Subject
- Mathematics
- Chapter
- Properties of Triangles
JEE Advanced 2015 · Paper 1 · Mathematics · Properties of Triangles
Column I Column II (A) In a triangle ∆ XYZ let a, b and c be the...
| Column I | Column II | |||
| In a triangle let be the lengths of the angles , respectively. If \lambda = \dfrac{\sin \left(X - Y\right)}{\sin Z}n\cos \left(n\pi\lambda\right) = 0 | ||||
| \left(B\right)\delta XYZ,a, b and cX, Y and Z1 + \cos 2x - 2\cos 2y= 2\sin x \sin y of \dfrac{a}{b} | ||||
| \left(C\right){\mathbb{R}}^{2},\sqrt{3}\overset{^}{i} + \overset{^}{j}, \overset{^}{i} + \sqrt{3}\overset{^}{j}\beta\overset{^}{i} + \left(1 - \beta\right)\overset{^}{j}X, Y and ZOZ\overset{\to}{OX}\overset{\to}{OY}\dfrac{3}{\sqrt{2}} is (are) | \left(R\right)3 | Suppose that denotes the area of the region bounded by and where Then the value (s) when and , is (are) | \left(S\right)5 | |
Options
- Aa-p,r,s;b-p;c-p,q;d-s,t;
- Ba-q,r,s,t;b-q,r,s,t;c-r,s,t;d-q,r,s;
- Ca-q;b-r;c-r,s;d-r,s;
- Da-q,r,s,t;b-t;c-r,s,t;d-q,r,s,t;
Correct answer
A. a-p,r,s;b-p;c-p,q;d-s,t;
Step-by-step solution
\left(A\right) \lambda = \dfrac{\sin \left(X - Y\right)}{sin Z}\dfrac{\sin X \cos Y - \cos X \sin Y}{\sin Z}\dfrac{acosY - bcosX}{c}\dfrac{a\left(\dfrac{{a}^{2} + {c}^{2} - {b}^{2}}{2ac}\right) - b\left(\dfrac{{b}^{2} + {c}^{2} - {a}^{2}}{2bc}\right)}{c} = \lambda\dfrac{{a}^{2} - {b}^{2}}{{c}^{2}} = \lambda2\left({a}^{2} - {b}^{2}\right) = {c}^{2}∴ \lambda = \dfrac{1}{2}∴ \cos \left(\dfrac{n\pi}{2}\right) = 0∴ n = 1, 3, 5
Solving
(rejected)
\left(C\right) OY ≡ y = \sqrt{3}xOX ≡ y = \dfrac{1}{\sqrt{3}}x∴OX, OYy = x∴ \left|\dfrac{x - y}{\sqrt{2}}\right| = \dfrac{3}{\sqrt{2}}\dfrac{\beta - \left(1 - \beta\right)}{\sqrt{2}} = \pm \dfrac{3}{\sqrt{2}}2\beta - 1 = \pm 3\beta = 2\beta = - 1
Area
Required value
Area= Shaded region area under parabola.
Required value