JEE Advanced2012MathematicsSequences and SeriesActual
Let a₁, a₂, a₃, . . be in harmonic progression with a₁=5 and a₂₀=25 . The least positive integer n for which a_ n < 0 is
Options
- A22
- B23
- C24
- D25
Correct answer
D. 25
Step-by-step solution
a₁, a₂, a₃, are in H.P. array l 1 a₁ , 1 a₂ , 1 a₃ are in A.P. 1 a₁ = 1 5 and 1 a₂₀ = 1 25 1 a₁ +19 d= 1 a₂₀ 1 5 +19 d= 1 25 d= -4 475 Now 1 a_ n = 1 5 +(n-1) ( -4 475 ) Clearly a_ n 99 4 =24 3 4 n 25 Least value of n is 25 . array