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Suppose four distinct positive numbers a₁, a₂, a₃ and a₄ are in GP. Let b₁=a₁ , b₂=b₁+a₂, b₃=b₂+a₃ and b₄=b₃+a₄ . Statement 1 The numbers b₁, b₂, b₃ and b₄ are neither in AP nor in GP. Statement 2 The numbers b₁, b₂, b₃ and b₄ are in HP.

Options

  1. AStatement 1 is true, Statement 2 is true, Statement 2 is a correct explanation for Statement 1.
  2. BStatement 1 is true, Statement 2 is true, Statement 2 is not a correct explanation for Statement 1.
  3. CStatement 1 is true, Statement 2 is false.
  4. DStatement 1 is false, Statement 2 is true

Correct answer

C. Statement 1 is true, Statement 2 is false.

Step-by-step solution

Let a₁=1, a₂=2, a₃=4, a₄=8 b₁=1, b₂=3, b₃=7, b₄=15 Clearly, b₁, b₂, b₃ and b₄ are not in HP. Statement 2 is false.

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